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How to transform a line break into a character?

How to transform a line break into a character?

How to transform a line break into a character?

(OP)
Good morning all,

I've the following problem:
My cobol retrieve a field from a table and value of this field is a text note that could contain line breaks.

I need to remove the line breaks from the retrieved value and change it into a character value as "-".

I tried doing the following:

INSPECT WS-TEXT REPLACING ALL X"15" BY "-"  or
INSPECT WS-TEXT REPLACING ALL X"7B" BY "-"

but in both cases it doesn't work.Debugging this line no changes are applied to WS-TEXT.

Does anyone know which is the element corresponding with line break(X"7B" or X??) and if inspect command can be used?

Thanks and I hope you can help me.

 

RE: How to transform a line break into a character?

What COBOL and what platform, and how are you opening the file?

It is not possible for anyone to acknowledge truth when their salary depends on them not doing it.

RE: How to transform a line break into a character?

(OP)
the COBOL is my program while platform is Personal Communications 5.9 for windows.
file is a table where information is stored with break line.

RE: How to transform a line break into a character?

(OP)
I just tested both suggestions but unfortunately they doesn't works.

RE: How to transform a line break into a character?

(OP)
Thanks for you help!

I found that character in question is X"25" of EBCDIC.

Do you know if inspect command slow the perfomance of a program?

RE: How to transform a line break into a character?

COBOL is vendor and version; e.g. Micro Focus Visual COBOL 3.6
Mentioning EBCDIC was also helpful
Platform is O/S and version; e.g. Windows 7 sp 2
 

RE: How to transform a line break into a character?

So, the following should do the needed replacement:

CODE

INSPECT WS-TEXT REPLACING ALL X"25" BY "-"

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