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# if -then -else question

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## if -then -else question

(OP)
Hello,

i am a newbie and i have the C-like code:
------
if( x > 10){
x = x + 5 - y;
y = x;
}else{
y = 0;
x = 0;
}
------

and i would to figure how the above code would be in prolog.
So, i was trying :
------
(   X > 10
->  X is X + 5 - Y,
Y is X
;
Y is 0,
X is 0
) .
------

but i am not certain, is the line "X is X + 5 - Y" correct?

Thank you.

### RE: if -then -else question

(OP)
moreover, if we had

if ( x > 10 + y)
/*code*/

in prolog it would be like the code below ?

( X > 10 + Y
/*code*/
).

### RE: if -then -else question

X is X + 5 - Y fails when Y is different of 5.
In SWI-Prolog you can translate if then else by

#### CODE

(X > Y+10 -> <code-when-true>; <code-when-false>)
Care of parenthesis.

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