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Need to set cron job for 45 min time interval

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vipinhcl

vipinhcl

Programmer
Apr 21, 2010
30
US
Hi All,

I am not sure whether I am asking this on right forum or not but I have problem while setting the cron job.
I am trying to set the job run time for .sh file from every 1 hour to 45 min time interval, but unable to set the time.

I tried these two methods to set the time

0-59/45 * * * * * * * * exec /appl/prod/bin/test.sh >/dev/null 2>&1

*/45 * * * * * * * * exec /appl/prod/bin/test.sh >/dev/null 2>&1


and in both cases getting this error - crontab: error on previous line; unexpected character found in line.



Please suggest. Thanks in advance.

 
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Hi. I'm not quite sure whether I fully understand what you want, but I don't think Solaris supports the 59/45 expression. Perhaps use * 45 * * * <command>?

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Hi Ken,

Thanks for your reply. I need to run the job at 45 min time interval. For example if I set the test.sh file in cron starting at 00:00 then it should run at 00:00 AM then 00:45 AM then 01:30 AM then 02:15 AM then 03:00 AM then 03:45 AM etc. I mean at 45 minutes of time interval. To do this I used the above syntax but getting error. How can I do this?.

Please advice.
 
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I see, thanks for clarifying. I think what I would do in such circumstances woul be to include a sleep 2700 in the script so that it loops every 45 minutes. You could then simply kick it off once from cron (or init) and let it do it's stuff.

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Hmm... that would be an good option.

Thanks for your reply.
 
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Or you can make a wrapper and run every 15 minute:

* 0,15,30,45 * * * <command>?


And the you call the other script every third time.
 
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