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Many to one Select statement
3

Many to one Select statement

Many to one Select statement

(OP)
TABLE1:

group_san cond_san
--------- ---------
1 1
1 2
1 3
5 2
5 3
5 4
5 5
I need to find the group_san that contains the cond_sans
(1,2,3). The answer should be group_san is 1. I haven't
been able to figure it out.

If it was like below, it would be no problem, but it's
not!

group col col col col
1 1 2 3
5 2 3 4 5

RE: Many to one Select statement

select group_san from table1 where col_san in (1,2,3)
minus
select group_san from table1 where col_san not in (1,2,3);

this seems to work, I just played with it for a minute and
it seems to work fine....

RE: Many to one Select statement

select group_san from table1 where col_san in(1,2,3)
group by group_san having count(*) = 3;
(Provided col_san values unique to group_san)

RE: Many to one Select statement

select group_san
from (select distinct * from table1
where cond_san in (1,2,3))
group by group_san
having count(*)=3;

Eduard Stoleru
aeg@ziua.ro

RE: Many to one Select statement

SELECT GROUP_SAN
FROM TABLE1
WHERE GROUP_SAN IN (SELECT COND_SAN
                      FROM TABLE1)

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