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how to split the content of a directory

how to split the content of a directory

how to split the content of a directory

(OP)
I'm new to perl and I have a simple question .
How do I split he content of a directory

here is the content of the directory:

mai 11 10:25 .
oct 10 1997  ..
mai 05 05:57 index
mai 11 11:36 test.pl

I want each line to be an element of an array
and after that I want to remove the first and the second element.

tks
Annie
;o)

RE: how to split the content of a directory

Use opendir and readdir.  Here's a little snippet of code to illustrate:

opendir(MYDIR, ".");    #Open a new directory handle.

# Read each file name from the directory handle.  When
# we run out of file names, the while will fail and
# we'll move on.
while ( $Current_File = readdir(MYDIR) ) {

    # Ignore "." and ".." (Optional)
    if ( $Current_File =~ /\.¦\.\./ ) {
        next;
    }

    Do your file processing here
}


Note:  I've just tapped this in from memory, and at my age that can be a bit dodgy ;^)  You might need to sort out any missing braces, or the regexp might be a little suspect.

Hope it puts you on the right track though.  Additionally, you can do a perldoc -f opendir or perldoc -f readdir to see the online docs.

Hope this helps.

RE: how to split the content of a directory

Try:

opendir DIR,".";
@filelist=grep { /^./ } readdir DIR;
closedir DIR;

then @filelist contains every element in the dir that DOESN'T start with "." (assuming that's what you want to get rid of)

RE: how to split the content of a directory

Hum...

@files = glob( "*" );

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