XPath WildCard Help

[stsuing]

What is the XPath syntax to do the following

Here is the XML
<?xml version="1.0" encoding="utf-8" ?>
<clientAddressRanges xmlns="

http://www.test.com/test">

<clientAddressRange start="192.128.133.0" end="192.128.133.255" />
<clientAddressRange start="192.128.134.0" end="192.128.134.255" />
</clientAddressRanges>

I want to find the node by the first 3 octets of ip. For example get me the node that has "192.128.134" in a start attribute.

Something like...
"clientAddressRanges/clientAddressRange[matches(@start,'" & "192.128.134"& "')]"

Any help is appreciated.

 

[tsuji]

If no extension function is used, split can be awkward. For ip address specific struction, brut-force can be done like this.
[tt]
<xsl:stylesheet version="1.0" xmlns:xsl="

http://www.w3.org/1999/XSL/Transform"

xmlns:dfns="

http://www.test.com/test">

<xsl:template match="dfns:clientAddressRanges">
<xsl:for-each select="dfns:clientAddressRange/@start">
<xsl:variable name="ip" select="." />
<xsl:variable name="c1" select="substring-before($ip,'.')" />
<xsl:variable name="t1" select="substring-after($ip,'.')" />
<xsl:variable name="c2" select="substring-before($t1,'.')" />
<xsl:variable name="t2" select="substring-after($t1,'.')" />
<xsl:variable name="c3" select="substring-before($t2,'.')" />
<xsl:if test="concat($c1,'.',$c2,'.',$c3)='192.128.134'">
[blue]<xsl:comment>A match has been found---do something here.</xsl:comment>[/blue]
</xsl:if>
</xsl:for-each>
</xsl:template>
</xsl:stylesheet>
[/tt]