XML to XML with XSL multiple elements

[strut]

i have a document a.xml with tags

<OldPhone>
<PhoneNumber>123-456-789</PhoneNumber>
<Description>HOME</Description>
</OldPhone>
<OldPhone>
<PhoneNumber>222-777-3333</PhoneNumber>
<Description>WORK</Description>
</OldPhone>

i need to get to b.xml that looks like this.

<tag name=IM2>123-456-789</tag>
<tag name=IM3>222-777-3333</tag>

I have created an XSL document that will put the first number into both fields, but i can not figure out how to get the work and home phone seperate.

my xsl

<tag name=&quot;IM2&quot;>
<xsl:value-of select=&quot;.//OldPhone/Number&quot;/>
</tag>


this gives the first phone number in both fields. Ideas?

 

[FredHelm]

You might want to use the xsl:choose function to select out the work number. The xsl below should give you a start with the corresponding xml located after it.

Fred

<xsl:stylesheet version=&quot;1.0&quot; xmlns:xsl=&quot;

http://www.w3.org/1999/XSL/Transform&quot;>

<xsl:template match=&quot;/&quot;>
<root>
<xsl:for-each select=&quot;//OldPhone&quot;>
<tag>
<xsl:attribute name=&quot;name&quot;>
<xsl:choose>
<xsl:when test=&quot;Description='HOME'&quot;>IM2</xsl:when>
<xsl:when test=&quot;Description='WORK'&quot;>IM3</xsl:when>
</xsl:choose>
</xsl:attribute>
<xsl:value-of select=&quot;PhoneNumber&quot;/>
</tag>
</xsl:for-each>
</root>
</xsl:template>
</xsl:stylesheet>

XML:
<Root>
<OldPhone>
<PhoneNumber>123-456-789</PhoneNumber>
<Description>HOME</Description>
</OldPhone>
<OldPhone>
<PhoneNumber>222-777-3333</PhoneNumber>
<Description>WORK</Description>
</OldPhone>
</Root>