Value of varibable into a hidden field

[jewel464g]

var count = 0

if (document.frmTest.q1.value == "T") {
count++;
}

if (document.frmTest.q2.value == "T") {
count++;
}

if (document.frmTest.q3.value == "T") {
count++;
}

if (document.frmTest.q4.value == "T") {
count++;
}

if (document.frmTest.q5.value == "T") {
count++;
}

if (document.frmTest.q6.value == "T") {
count++;
}

if (document.frmTest.q7.value == "T") {
count++;
}

if (document.frmTest.q8.value == "T") {
count++;
}

if (document.frmTest.q9.value == "T") {
count++;
}

if (document.frmTest.q10.value == "T") {
count++;
}

count = count * 10;


How do I get the value of count into a hidden field within my form.

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When faced with a decision, always ask, 'Which would be the most fun?'

 

[simonchristieis]

try this

document.forms['frmTest'].elements['myHiddenField'].value = count

 

[kaht]

Assume that the name of your hidden field is named hiddenField. If that's the case, then the last line of the function would be:

document.frmTest.hiddenField.value = count;

-kaht

 

[simonchristieis]

In case you are wondering - my suggestion and kaht's are exactly the same.

 

[BillyRayPreachersSon]

Why not replace all those ugly if statements with one if statement within a loop? It also means that if you add or remove fields, it becomes easy to change the code to suit:

for (var loop=1; loop<11; loop++) {
   if (document.forms['frmTest'].elements['q' + loop].value == "T") count++;
}

Hope this helps,
Dan

 

[LFI]

Shoot, while you're at it, as long as you're going to multiply by 10 at the end, intead of count++, just make each one: count += 10;

--Dave