switch-case and char arrays

[cadbilbao]

Is it possible to make a switch-case with char arrays?

I am trying with this piece of code:


char *value;
...
switch (value) {
case "John":
printf("Your name is John\n"
break;
case "Tom":
printf("Hello, Tom!\n"
break;
}

But I get this error:
<<error C2450: switch expression of type 'char *' is illegal
Integral expression required >>

Any help?

 

[meadandale]

You cannot switch on a pointer. You need to dereference it:

switch(*value){
...
}

Regards,

Charles

 

[Zyrenthian]

Only one problem... switch *value will only compare the first character. I would change it to if's instead

if(!strcmp(value,&quot;John&quot
{
...
}
else if(!strcmp(value,&quot;Tom&quot
{
...
}
else
{
... // default in switch
}

This could possibly be a bit big though.

Matt

 

[Cagliostro]

in case statement you can use only char's(not strings or char arrays), short integers, long integers and all of them must be constants, not variables. John Fill

ivfmd@mail.md

 

[chiph]

Cadbilbao -

Do like Zyrenthian says and use a if..elseif..else structure with strcmp, wcscmp, or _tcscmp.

Chip H.

 

[abp]

You can reduce the size of such
an if...else construct with this trick.

char *names[]= {&quot;John&quot;, &quot;Dick&quot;, &quot;Harry&quot;, NULL};
char **p;

char *value=&quot;Harry&quot;;
for ( p=names; *p!=NULL; p++ )
{
if ( !strcmp(value, *p))
printf(&quot;I am %s&quot;, *p);
}


Anand
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