Hi again,
When I use a StreamReader to open a file as follows:
StreamReader finschema = new StreamReader("dispPubs.xsl");
I get the following error:
Could not find file "C:\WINDOWS\system32\dispPubs.xsl"
Is there any way to open a file in the current directory without hardcoding it?
Thanks.
Lumstar
______________________________________
And The Star Continues To Shine....
When I use a StreamReader to open a file as follows:
StreamReader finschema = new StreamReader("dispPubs.xsl");
I get the following error:
Could not find file "C:\WINDOWS\system32\dispPubs.xsl"
Is there any way to open a file in the current directory without hardcoding it?
Thanks.
Lumstar
______________________________________
And The Star Continues To Shine....