simple regular expression question

[smsinger3]

I need to validate a number this is 8 digits and no more. I use this validation expression:

^[\d]{8}

However, I can still type in more than 8 digits and it returns a true. How can I change it to return a false if more than 8 digits are entered?

Thank you for your help!

SteveS
stevensinger123-tt@yahoo.com

 

[cappmgr]

Steve:
Give this a shot ^\d{8}$ the dollar sign is the end of the string.
Marty

 

[AngieR]

Try this \d{8}....it works for me.

 

[cappmgr]

Intersting!
Is it a regular expression validator for a field on a ascx or aspx or is it in the codebehind? I am at a disadvantage here at work because we are not doing .NET and I have no real ide to drop in the rev. This is what I wrote to test rexex's. Without telling the regex that it's the end of the string with the $ it will allow 123456789 to be true.

I miss writing cgi scripts using PERL. Have to make a living!
Marty


using System;
using System.Text.RegularExpressions;

namespace regextest8 // Defining Namespace
{
class MainClass // Defining Class
{
public static void Main(string[] args) // Program Entry Point
{
string _input;
Console.Write("Enter string: "
_input = Console.ReadLine();
while (!(_input.Equals("end&quot))
{
MainClass.mymatch(_input);
Console.Write("Enter string: "
_input = Console.ReadLine();
}
}
public static void mymatch(string _input)
{
Match MyRegMatch = Regex.Match(_input,"^\\d{8}$"
if(MyRegMatch.Success)
{
Console.WriteLine("good string"
}
else
{
Console.WriteLine("bad string"
}
}//end match
}
}

 

[smsinger3]

This was in a regular expression validation. This is what I used: ^\d{8}$

It works like charm

SteveS