sed problem with variable

[harwooddale]

Hi,
I am having a problem passing a variable to the sed command.

For example:

$filename=13017105.ack

#I then want to count how many lines there are in the file,
#but need the output to be a number.

#The output looks something like:
#19 13017105.ack

#command to try and just retrieve number:
filename1=`wc -l $filename | sed 's/$filename//g'`

This doesn't work.

If I replace $filename with 13017105.ack it works perfectly!

Any Ideas

Any help appreciated


James

 

[Ygor]

Dont use quotes around the variable

filename1=`wc -l $filename | sed s/$filename//g`

Or just use...

filename1=`wc -l < $filename`

 

[vgersh99]

#command to try and just retrieve number:
filename1=`wc -l $filename | sed &quot;s/$filename//g&quot;`

OR (isn't it what you REALLY want?)

#command to try and just retrieve number:
filename1=`wc -l < $filename`

vlad
+----------------------------+
| #include<disclaimer.h> |
+----------------------------+

 

[pavNell]

Perhaps...

#!/bin/sh

filename=13017105.ack
num_lines=`wc -l < $filename | sed 's/ //g'`

echo &quot;$num_lines $filename&quot;


An example of referencing shell variables in sed...

#!/bin/sh

myvar=&quot;foo&quot;
sed 's/'&quot;$myvar&quot;'/boo/g' inputfile