Retrieving the system date in MMDDYY format 1

[DayLaborer]

How can I get the two digit year from the command line?

The closest I've come is:

FOR /F "TOKENS=1,2,3,4 DELIMS=/ " %A IN ('DATE/T') DO SET TEMPYEAR2=%B%C%D

but that returns
10032006
and I would like only
100306

Thanks!

 

[DayLaborer]

...if this is the wrong forum:
(1) my apologies, and
(2) kindly point me to the correct forum for this question.

Thanks!

 

[LWComputingMVP]

Use:

%date:~-2%

For example:
Set mm=%date:~4,2%
Set dd=%date:~7,2%
Set yy=%date:~-2%
Set yyyy=%date:~-4%

 

[DayLaborer]

Thank you, LW! Terrific (star)!