Regular expression question

Masali · Dec 6, 2003

Hi,

I have a variable that contains HTML with certain tags like {NEWS}, {DIARY}, {ETC}. So a template could look like this:

Code:

<html>
<head>
<title>Test</title>
</head>
<body>
<table border=&quot;1&quot; cellspacing=&quot;1&quot; width=&quot;100%&quot; id=&quot;AutoNumber1&quot;>
  <tr>
    <td width=&quot;50%&quot;>{NEWS}</td>
    <td width=&quot;50%&quot;>{DIARY}</td>
  </tr>
</table>
</body>
</html>

I want to make a loop that foreach keyword (tag) replaces the tag with the appropriate content. Something like this..

Code:

while($tag=regexpression)
{
$tag=$content[$tag];
}

Please advice

Masali

sleipnir214 · Dec 6, 2003

PHP's preg_replace() function can take as the "find" and "replace" parameters two arrays.

If your HTML template is in a single string, preg_replace() could do all the replacements in a single invocation.

The the sample code at

http://us3.php.net/manual/en/function.preg-replace.php

Want the best answers? Ask the best questions:

http://www.catb.org/~esr/faqs/smart-questions.html

TANSTAAFL!!

Masali · Dec 6, 2003

yes, i know that, but the tags will be replaced with different content according to the tagname.. so for every tag there is different content that needs to be prepared when I know the tagname. That's why i want the loop.

I know how to do it in Perl, but I have just started using PHP instead.. This is what I need, but in PHP instead of Perl

Code:

while($template=~/\{(.*)\}/ig)
{
if($1 eq &quot;NEWS&quot;)
{
$1=&quot;The news are...&quot;;
}
elsif($1 eq &quot;DIARY&quot;)
{
$1=&quot;My diary contains...&quot;;
}
}

sleipnir214 · Dec 6, 2003

If you hand preg_replace two arrays, it will do exactly what you loop in perl does.

The first element in the search array is replaced with the first element in the replacement array. Etc.

Want the best answers? Ask the best questions:

http://www.catb.org/~esr/faqs/smart-questions.html

TANSTAAFL!!

Masali · Dec 6, 2003

Can you please show me some example code. I don't quite get it..

Masali

KarveR · Dec 6, 2003

unashamedly stolen from php.net comments for preg_replace (

http://uk2.php.net/manual/en/function.preg-replace.php

- I was looking at this very thing yesterday.)

<?php
$string = "The quick brown fox jumped over the lazy dog.";

$patterns[0] = "/quick/";
$patterns[1] = "/brown/";
$patterns[2] = "/fox/";

$replacements[2] = "bear";
$replacements[1] = "black";
$replacements[0] = "slow";

print preg_replace($patterns, $replacements, $string);

/* Output
======

The bear black slow jumped over the lazy dog.

*/

/* By ksorting patterns and replacements,
we should get what we wanted. */

ksort($patterns);
ksort($replacements);

print preg_replace($patterns, $replacements, $string);

/* Output
======

The slow black bear jumped over the lazy dog.

*/

?>

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Regular expression question

Masali

Programmer

sleipnir214

Programmer

Masali

Programmer

sleipnir214

Programmer

Masali

Programmer

KarveR

MIS

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