regex to filter high bit characters 1

[dougcranston]

I have a need to replace all high bit codes from content gathered via a form, prior to writing it to a database. Server is Windows 2000 Server, and I do most of my server and client side in Javascript/Jscript.

What I am shooting for is after running a regex replace all other characters EXCEPT FOR:

Dec 09
Dec 10
Dec 13
Dec 32 - 126

All others I want to replace with a "blank" or Dec 32

Is their an easy way to accomplish this in Javascript Regex?

I have searched the web but I suspect I am either using the wrong search terms or it just never has come up, which I would find hard to believe.

Thanks in advance.

DougCranston

 

[BillyRayPreachersSon]

So basically, any character that is not a tab, carriage return , or linefeed character, you want replaced with a space?

Dan


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[tsuji]

I don't know... Bruteforce is something like this.
[tt]
function pchar_reduction(s) {
var p;
p="\n"+"\t"+"\r";
for (var i=32;i<127;i++) {
p+=(i==91||i==92|i==93||i==94)?"\\"+String.fromCharCode(i):String.fromCharCode(i);
}
p="["+p+"]"; //building pattern completed

var re=new RegExp(p,"g");
return s.match(re).join("");
}
[/tt]
- tsuji

 

[dougcranston]

Dan,

Yes.. What I want to retain is "normal" alpha numeric chars along with the \t \r and \n.. And replace any other special or high bit characters with a blank.

I am convinced that the problem is related to these "other" characters choking the app when it tries to load to the database. I suspect that some of my users have been cutting text from Word or another source but have not been able to confirm or prove it conclusively.

Thanks,

DougCranston

 

[dougcranston]

tsuji,

It looks like you have created/provided the solution I have been looking for.

I was afraid I was going to have to create 130+ individual replace statements and from what I think the code you have provided, does that in just a few lines.

Will try that here in a few minutes.

Thanks so much for taking the time to respond and with a solution that looks like it will solve my problem.

Thanks for your input.

DougCranston