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printing leading zeros
- Thread starter NPI
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- #2
I auppose if might be poor forum to answer my own question but I just figured out the answer for integers.
printf( "%.3d\n", v_nmbr ) will yield 001
I suppose that the question still remains on doing this with reals.
i.e what if v_nmbr=1.1?
printf( "%.3d\n", v_nmbr ) will yield 001
I suppose that the question still remains on doing this with reals.
i.e what if v_nmbr=1.1?
- Thread starter
- #4
Hey Everyone,
Thanks for your help.
It turns out that the answer is a combination of things I learned here and elsewhere.
To print any number padded with zeros just place a 0 as the first character in the format specifier.
For an integer: %03d
For a real: %03.1f
awk 'BEGIN{v_nmbr=1; printf("%03d\n", v_nmbr )}'
001
awk 'BEGIN{v_nmbr=1.1; printf("%05.1f\n", v_nmbr )}'
001.1
Thanks for your help.
It turns out that the answer is a combination of things I learned here and elsewhere.
To print any number padded with zeros just place a 0 as the first character in the format specifier.
For an integer: %03d
For a real: %03.1f
awk 'BEGIN{v_nmbr=1; printf("%03d\n", v_nmbr )}'
001
awk 'BEGIN{v_nmbr=1.1; printf("%05.1f\n", v_nmbr )}'
001.1
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