php date question

[axman505]

Hello,

everyime i load a certain page, i want to be able to calulate a date that is exactly 2 weeks from today, excluding weekends. Is there any easy way to accomplish this?

Or does anyone have prewritten code?

Thanks,

 

[sleipnir214]

Do you mean that you want to calculate a date that is 14 weekdays ahead of a given date?



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[JRBeltman]

$twoweeks = date("M-d-Y",mktime(0,0,0, date("m"), date("d")+14, date("Y")));
echo $twoweeks."<br>";

How do you mean excluding the weekend?
Do you mean that if it is a Saturday or Sunday it should correct the date to dispay the coming Monday?

JR
As a wise man once said: To build the house you need the stone.
Back to the Basics!

 

[kenrbnsn]

You can also use the strtotime() function:

$twoweeks = date("M-d-Y",strtotime("+2 weeks"));

Ken

 

[sleipnir214]

I'm assuming that you're wanting x number of days from a valid list of days to count.

<?php

function add_specified_days ($start_date, $number_of_days, $valid_days)
{
        $days_of_week = array (1, 2, 4, 8, 16, 32, 64);
        $counter = 0;
        $test_date = strtotime($start_date);

        while ($counter < $number_of_days)
        {
                $test_date += 86400;

                $dow = $days_of_week[date ('w', $test_date)];

                if ($dow & $valid_days)
                {
                        $counter++;
                }
        }

        return date('Y-m-d', $test_date);
}

// Calculate the third parameter ($valid_days) by bitwize-oring
// (or adding -- the two operations are equivalent on this
// data) numbers from this table:
//
// su  m   t   w   th  f   sa
// 1   2   4   8   16  32  64
//
// If you want to count only weekdays, use 62
// If you want to count only weekends, use 65
// If you want to count only Sundays, use 64


$a = '2004-07-01';

//14 weekdays later
print add_specified_days($a, 14, 62);

print "\n";

//14 weekend days later
print add_specified_days($a, 14, 65);

print "\n";

//a month of Sundays later
print add_specified_days($a, 28, 64);

print "\n";
?>

This returns:

2004-07-21
2004-08-15
2005-01-08

Which seems correct by my hand-calculations.



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[JRBeltman]

Whow! That looks great (as per usual). Whish I could somehow store these threads!

Thanks m8

JR
As a wise man once said: To build the house you need the stone.
Back to the Basics!