Parenthesis Expected error in ASP.NET! 1

[z07924]

OrigPath = OrigPath.Replace(Convert.ToChar("\&quot,Convert.ToChar("\\&quot);

I want to replace single backslash with double backslash.
Here I am getting error in the above line as given below.

1: ) expected
2: Invalid expression term ''
3: Newline in constant

I am getting these errors. Please help me out.I would highly appreciate any help.

Thanks.

 

[LFCfan]

does this help? i have to leave in a minute so i cant test it

OrigPath = OrigPath.Replace(Convert.ToChar("\\"),Convert.ToChar("\\\"));

ie an extra backslash in each place

i think (i'm pretty new to all this) that C# ignores the first backslash it finds (even inside a "....." string) unless it specifies a newline

eg "Brad Pitt \n" would mean "Brad Pitt" followed by a newline character

hope this helps/makes sense

 

[z07924]

It doesn't help me out. It is giving the same error.
I would highly appreciate any help.

Thanks.

 

[Isadore]

Might try:

OrigPath = OrigPath.Replace("/","//&quot

 

[davecapone]

Hi Z,

You got a couple problem here, first off you are using the ToChar function. A char in C# is a 1 character string so there will be an error in that function although you are not seeing it yet because of your other problem.

In C# a simple \ denotes a newline character so it must be escaped out. Therefore your correct code should be:

OrigPath = OrigPath.Replace("\\","\\\\"

Without the Convert.toChar functions.

 

[z07924]

Thanks a lot. It is working now. I had a meeting yseterday thats why I couldn't reply you immediately.

 

[LFCfan]

Dave,

why does it need four backslashes? i'm most probably being dim here (it being friday afternoon). does it take the first one to be a newline character, the second to be an ordinary backslash character, the third again newline, and the fourth again a normal backslash?
if you wanted to replace "\" with "\\\" would it be

OrigPath.Replace("\\", "\\\\\\&quot

??

Actually when i think about it that sort of makes sense. sort of... but i was expecting in z's case it would only need three backslashes....


thanks

 

[Isadore]

That is what I was trying to say earlier, should have used "backslashes", but a ratio of "one" to "two" in the string replacement.