Need help for awk with if.. else..

[6656]

Hi All,

Below codes will print the messages for each of unmatched records. How to correct it to print only one 'Not Found' message at the end of a file if the word is not found?

#-------- Script --------
read string?'[Enter the old name]: '
awk '{ if ( $1 == word )
print "[ The new name is]: " $2
else print " Not FOUND!"
}' word="$string" $HOME/old_new.txt

Thanks,
Mike

 

[vgersh99]

read string?'[Enter the old name]: '
awk '{ if ( $1 == word )
print "[ The new name is]: " $2
else notFound++;
} END { if (notFound) print " Not FOUND!"}' word="$string" $HOME/old_new.txt

vlad
+----------------------------+
| #include<disclaimer.h> |
+----------------------------+

 

[CaKiwi]

Untested, but may get you started

awk '{ if ( $1 == word ){
print &quot;[ The new name is]: &quot; $2
fnd = 1
}
}
END{ if (!fnd) print &quot; Not FOUND!&quot; }'


CaKiwi

&quot;I love mankind, it's people I can't stand&quot; - Linus Van Pelt

 

[6656]

Thanks Vlad and Cakiwi,

Both of your codes returened the closed results I expected. However the &quot;Not Found&quot; message will be printed in either conditions (true/fails) met. How to fixed?

Thanks again,
Mike

 

[vgersh99]

could you post a sample file you're trying to parse, pls!

vlad
+----------------------------+
| #include<disclaimer.h> |
+----------------------------+

 

[6656]

It works now by adding a declare fnd=0 or notfound=0 befor awk.

Mike