Mid problem

[JavaDude32]

I have a loop that essentially breaks down a string character by character (if there is a charAt or any type of method such like please point me to it). It refuses a variable as a 2nd argument even with the CLng conversion function.

Dim intTemp
For I = 0 to Len(Session("mapFeatures&quot)-1 Step 1
intTemp = Session("mapFeatures&quot
intTemp = Mid(intTemp,CLng(I),1)
intTemp = CInt(intTemp)
mapFeatures(intTemp) = "yes"
Next

 

[jpbrassard]

[tt]InStr(string1, string2)[/tt] is the analagous function in VB. It returns a long value, either the position of string2 in string1, a zero if not found, or null if string1 is a zero-length string.

There is also the InStrRev function, which works in much the same way, only going from right to left.

HTH,
jp

 

[WZUP]

Is it giving you an error? if so at which line?

One thing i see is that your writing over the previous
value with each "mid"

do you want: intTemp=inTemp & Mid(inTemp,CLng(I),1) ?

 

[JavaDude32]

It won't look in the right spot, what I want to do is see what character is in the 3rd slot in the string, sorta like a C++ char array since I'm using this to store array slot values.

 

[JohnYingling]

First
intTemp = Mid(intTemp,CLng(I),1)
fails for I=0 since Mid starts at 1

Dim intTemp
dim sTemp
sTemp = Session("mapFeatures&quot
For I = 1 to Len(sTemp) Step 1
intTemp = Mid(sTemp,I,1)
'''??? Where us the mapfeatures Array defined
mapFeatures(intTemp) = "yes"
Next

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[JavaDude32]

Thanks a lot, darn the differences in programming languages argh. I'm too used to java\C++.

 

[JohnYingling]

VB.Net will be more to your liking then.
Use "pure" .NET framework methods like
For I = 0 To sTemp.length - 1
If stemp.Substring(I,1)
Next

or stay VB

For I = 1 To Len(stemp)
If Mid(stemp,I,1)
Next

http://www.VBResizer.com

Forms/Controls Resizing/Tabbing Control

http://www.VBCompare.com

Compare Code (Text)

http://www.VBSortGen.com

Generate Sort Class in VB or VBScript