I have included the LIKE operator in my selection criteria. The problem is it doesn't seem to be working. As an example, LIKE for the IPAdress of 127.* gives me 110.2.1.1.
Can anyone tell me what I am doing wrong? Here is my selection criteria. I am using Crystal7.
{CV3EnumReference.ColumnName} = "AuditType" and
{CV3EnumReference.ReferenceString} = {?AuditType} and
{SCMLogonAudit.CreatedWhen} >= {?Start Date and Time} and
{SCMLogonAudit.CreatedWhen}<={?End Date and Time} and
if {?Workstation} = "All" then true
else
{SCMLogonAudit.Workstation} like {?Workstation}
and
if {?User} = "All" then true
else
{SCMLogonAudit.Username} like {?User}
and
if {?IPAddress} = "All" then true
else
{SCMLogonAudit.IPAddress} like {?IPAddress}
Can anyone tell me what I am doing wrong? Here is my selection criteria. I am using Crystal7.
{CV3EnumReference.ColumnName} = "AuditType" and
{CV3EnumReference.ReferenceString} = {?AuditType} and
{SCMLogonAudit.CreatedWhen} >= {?Start Date and Time} and
{SCMLogonAudit.CreatedWhen}<={?End Date and Time} and
if {?Workstation} = "All" then true
else
{SCMLogonAudit.Workstation} like {?Workstation}
and
if {?User} = "All" then true
else
{SCMLogonAudit.Username} like {?User}
and
if {?IPAddress} = "All" then true
else
{SCMLogonAudit.IPAddress} like {?IPAddress}