IP RANGE/CLASS QUESTION.

[gman10]

Hello all-

I hope this is the right forum for this question, if not I'll post it where necessary.

Well, here goes:

I'm trying to work out the right IP scheme/CLASS for a 3 site assessment.
There are 3 buildings. each will have 500 users (total 1500 users) all will need a PC so all must have individual IP addresses and each building should be in different subnets (unless there's a better way, I've been told for management purposes 3 different subnets makes sense) anyway..
My question, what is the right CLASS/range to use for this scenario? I'm thinking maybe a CLASS "A" ie.

10.10.1.1-10.10.1.500/24 SITE 1
10.10.2.1-10.10.2.500/24 SITE 2
10.10.3.1-10.10.3.500/24 SITE 3

Would this do it? just curious ..

Thanks everyone for all the massive support!

gman

 

[plshlpme]

to have 500 hosts on each segment youll need a /23
which will give you 512 total hosts and 510 usable hosts

so say:
SITE 1 10.10.0.0 255.255.254.0 --> 10.10.0.0 to 10.10.1.255
SITE 2 10.10.2.0 255.255.254.0 --> 10.10.0.0 to 10.10.3.255
SITA 3 10.10.4.0 255.255.254.0 --> 10.10.0.0 to 10.10.5.255

in your above example you specify a /24, there can only be 256 host address in a /24 as a /24 can be rewritten as:
255.255.255.0 leaving only 8 bits left for hosts, 2^8=256

so to get 500 hosts youll need 9 bits for hosts as 2^9=512.