I have the below code. [code] i

[gagz]

I have the below code.

if ($dir = @opendir("./")) {
  while (($file = readdir($dir)) !== false) {
    #do some stuff
  }  
  closedir($dir);
}

is there a way to sort opendir? Ie if files are named file-01.txt file-02.txt?

I could probaby fill and array then sort that, but don't want to add that step...

Thanks.

 

[sleipnir214]

That's the only way to do it.

I suppose you could take the output of an "ls" command and parse it, but that would be more work than stuffing the data into an array. Want the best answers? Ask the best questions:

http://www.tuxedo.org/~esr/faqs/smart-questions.html

TANSTAAFL!

 

[BB101]

u can always collect all the files/folders from opendir and run them through a custom sort routine. --BB