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How to convert string variable to integer?
- Thread starter vovan1415
- Start date
sleipnir214
Programmer
Perl doesn't differentiate variables by types, only by contexts.
If a scalar-context variable holds something that can be interpreted as a number, perl will do so automatically at need. ______________________________________________________________________
TANSTAAFL!
If a scalar-context variable holds something that can be interpreted as a number, perl will do so automatically at need. ______________________________________________________________________
TANSTAAFL!
Yep, that's right - but an example may help:
$myVariable = "27822";
$anotherVariable = 23;
$yetAnother = "Hello World";
## Use as a string - add together
$yetAnother = $yetAnother." ".$myVariable;
## The value of $yetAnother is now "Hello World 27822"
## Now lets use it as a number
$myVariable = $myVariable + $anotherVariable;
## The value of $myVariable is now 27845
So long as the variable only contains numbers (and a period in the case of floating point fractions) it can be treated just like a number! One of the beauties of Perl!!!
$myVariable = "27822";
$anotherVariable = 23;
$yetAnother = "Hello World";
## Use as a string - add together
$yetAnother = $yetAnother." ".$myVariable;
## The value of $yetAnother is now "Hello World 27822"
## Now lets use it as a number
$myVariable = $myVariable + $anotherVariable;
## The value of $myVariable is now 27845
So long as the variable only contains numbers (and a period in the case of floating point fractions) it can be treated just like a number! One of the beauties of Perl!!!
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