How to access upper node XML element inside lower node XSL template

[SilverStray]

Hi,

I'd like to know how, if even possible, to access XML data in the upper node when I am working on a XSL template for the XML's lower node. For the XML code below, I have the excerpt of the XSL template match for the node 'assyData'.

--XML Code---

-<step>
<name>SAW</name>
<desc>Sawing Process</desc>
-<assyStepData>
-<assyData>
<compType>DIE</compType>
<soRemarks>Die in Saw Remarks</soRemarks>
<operInstruction>Die in Saw Instruction</operInstruction>
<ppData />
</assyData>
-<assyData>
<compType>ANGEL</compType>
<soRemarks>Dummy Saw SO Remarks</soRemarks>
<operInstruction>Dummy Saw Instruction</operInstruction>
<ppData />
</assyData>
</assyStepData>

</step>

->>>>And here's my XSL Code:

<xsl:template match="assyData">

<xsl:template match="assyData">
<xsl:choose>
** <xsl:when test="../name='SAW'">
<xsl:text>SAW:</xsl:text>
<xsl:value-of select="soRemarks"/>
</xsl:when>
<xsltherwise>
<xsl:value-of select="soRemarks"/>
</xsltherwise>
</xsl:choose>
</xsl:template>

** In the problem area I pointed above, what I wanted
to do is to put a condition if the value of name in
the upper node under step is 'SAW'. But the portion

<xsl:when test="../name='SAW'">

obviously is not the right way for me in doing the
test condition.

Can anybody help me how i may do this?

thanks in advance.

*joni

 

[JSpicolli]

<xsl:when test="//name='saw'">