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gray out button at the end of images array
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It doesn't really make sense to set the image to disabled... I mean... an image is an image... not a form element. You can set the disabled property on form elements.
Cheers,
Jeff
[tt]Jeff's Page [/tt][tt]@[/tt][tt] Code Couch
[/tt]
Cheers,
Jeff
[tt]Jeff's Page [/tt][tt]@[/tt][tt] Code Couch
[/tt]
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[tt]<!-- quick test - disabled attribute on some form elements -->
<html>
<head>
<script language="javascript">
function doit(obj) {
alert(obj.disabled);
obj.disabled=!obj.disabled;
}
function imgdisabledattr_toggle() {
alert(document.images["xyz"].src + "\n" + document.images["xyz"].disabled);
document.images["xyz"].disabled=!document.images["xyz"].disabled;
alert(document.images["xyz"].src + "\n" + document.images["xyz"].disabled);
}
</script>
</head>
<body>
<form>
<input type="button" value="some_button" onclick="doit(this)" />
<img src="abc.gif" name="xyz" alt="an_image" onclick="doit(this)" />
<input type="text" onclick="doit(this)" />
</form>
<button onclick="imgdisabledattr_toggle()">toggle the image disabled attribute</button>
</body>
</html>
[/tt]
img can well be a form element and capture server-side upon submit action. Once disabled, it is not "greyed"; it is disabled nonetheless.
<html>
<head>
<script language="javascript">
function doit(obj) {
alert(obj.disabled);
obj.disabled=!obj.disabled;
}
function imgdisabledattr_toggle() {
alert(document.images["xyz"].src + "\n" + document.images["xyz"].disabled);
document.images["xyz"].disabled=!document.images["xyz"].disabled;
alert(document.images["xyz"].src + "\n" + document.images["xyz"].disabled);
}
</script>
</head>
<body>
<form>
<input type="button" value="some_button" onclick="doit(this)" />
<img src="abc.gif" name="xyz" alt="an_image" onclick="doit(this)" />
<input type="text" onclick="doit(this)" />
</form>
<button onclick="imgdisabledattr_toggle()">toggle the image disabled attribute</button>
</body>
</html>
[/tt]
img can well be a form element and capture server-side upon submit action. Once disabled, it is not "greyed"; it is disabled nonetheless.
Sorry if I appear a bit dense about this... but I have no idea what you are on. The code you posted does not use an image as a form element. You are merely setting a custom property on the image which has an ID - the custom property has no other effect... and the image will never be sent as part of the form submission regardless of what you do with this property.
Please correct me if I am wrong... but I just don't see what you are saying and what you are doing as making any sense.
Cheers,
Jeff
[tt]Jeff's Page [/tt][tt]@[/tt][tt] Code Couch
[/tt]
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