Finding most recent file on NT

[Guest_imported]

Hi,
How to find a most recent file generated in particular directory on NT.

Example: I have these files with different timestamps
File Name size Type Timestamp
1) abc1.txt 1KB txt 08/08/2001 2:32 PM
2) abc2.txt 1KB txt 08/07/2001 2:40 PM
3) abc3.txt 1KB txt 08/06/2001 2:00 PM

My result should be abc1.txt , as 1,2,3 in the file names generated randomly .
So i need to check the file abc*.txt files with the latest one. The result should give
one value ( abc1.txt ) .
Any help will be appreciated.

Thanks
Sam

 

[mcconmw]

Something along these lines should do it:

dir abc*.txt /o-d /b > c:\abc.txt
for /F "tokens=1" %%i in (c:\abc.txt) do (set abc=%%i & goto next)
:next

rem goto next would be on the same line as the for statement in a batch file.

Basically this batch file reads in all abc files with the newest one at the top. It then reads in the first line of the file and jumps out of the for loop. In place of the set command you can use any other command you need to meet your goals. Good luck.

 

[Guest_imported]

Thanks a lot for your prompt reply.
It worked fine in the NT script.