Find latest file

[Tim2525]

Hi All,

Excuse my simple qs. I am VERY new to scripting and writing a script that would find the latest file (time) created in this format "db2_backup_08/31/05_14:39". I would need to find the file and once found, parse out the date time. Can someone give me suggestions on the best way of doing this?

TIA,
Tim

 

[KenCunningham]

Something like:
ls -lt db2_backup* | head -1 | tr -s ' ' ' ' | cut -f9 -d ' '

Then do a similar cut for the date/time portion.

 

[daFranze]

if all the files are in one directory and the filename and creationtime are the same: use 'ls -lt' or 'ls -ltr' to sort files. If you need to sort the files by name you could use 'sort' command with -k options. Please check the 'man sort'

Best Regards, Franz
--
Solaris System Manager from Munich, Germany
I used to work for Sun Microsystems Support (EMEA) for 5 years in the domain of the OS, Backup and Storage

 

[Tim2525]

Thanks all for the replies. That did it...