If Right ({CLIENT.ClientName}, 3) = "Ltd" then "Yes" else
If Right ({CLIENT.ClientName}, 3) = "ltd" then "Yes" else
if Right ({CLIENT.ClientName}, 7) = "limited" then "Yes" else
if Right ({CLIENT.ClientName}, 7) = "Limited" then "Yes" else "No"
And then in the selection expert just picked all the ones equal to "Yes".
It seems to have brought back some results. Does anyone think this is corrct
Right ({CLIENT.ClientName}, 3) = "Ltd" or
Right ({CLIENT.ClientName}, 3) = "ltd" or
Right ({CLIENT.ClientName}, 7) = "limited" or
Right ({CLIENT.ClientName}, 7) = "Limited"
Display all of the records with this beside it, returning True or False. Check it against the actual data. If it's OK, put the boolian in the selection - it selects only those where the answer is True
Madawc Williams (East Anglia, UK). Using Windows XP & Crystal 10
The formula is fine but I can see just one problem. Say if there is a client name with Ltd in the name but has a different ending i.e. something in brackets.
Is there a function I could use to search a string for a particular string of characters.
I've looked at the Filter function but it keeps on saying that my client name field is not a string array.
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