Display the most recent jpg

[bopritchard]

i have a directory of images that are time stamped in their name like this cam20030829103721843.jpg...they get added to every few minutes...what i want to do is display only the most recent file as an image..

so img src=newestfile.jpg

thanks

 

[DRJ478]

You need to read in the directory listing and select the newest by filename or timestamp.

Read about the directory functions in the PHP manual:

http://ca2.php.net/manual/en/ref.dir.php

Work from there.

 

[jimoblak]

Here's a little clip from an image directory lister. You can tweak the last few lines to obtain the last element in the array to get your most recent image. I'm sure there is an easier way to get the most recent file by reading the system date but since you didn't share the URL for your dirty web cam, this is all I choose to offer.

// The subdirectory that stores cam shots
$short = "/camshots";
// The full system path of the cam shot subdirectory
$long = "/[URL unfurl="true"]www/joeuser/htdocs/camshots";[/URL]

function showdirectory($short,$long) {
  print (&quot;This lists images in a directory:<br>&quot;);
  if (is_dir($long))
  {
  if ($dh = opendir($long))
  {
  while (($filename = readdir($dh)) !== false)
  {
  if (($filename != &quot;.&quot;) && ($filename != &quot;..&quot;))
  {
  $files[]=&quot;$filename&quot;;
  }
  }
  closedir($dh);
  }
  }
  natcasesort($files);
  foreach ($files as $myfilename) {
  print (&quot;<a href=\&quot;$short/$myfilename\&quot;>$myfilename</a><br>&quot;);
  }
}

- - picklefish - -

Why is everyone in this forum responding to me as picklefish?