Date formatting

[bopritchard]

how can i take this file name strip out the first 3 and last 4 characters and format the remainder as a valid date/time

cam20030903150719820.jpg

 

[sleipnir214]

What are the extra three digits to be used for? Your example could be interpreted as "2003-09-03 15:07:19", but what do we do with the "820"? To the best of my knowledge, it's not part of a valid time/date stamp. I assume it's some kind of serial number or possible decimal seconds.

Anyway, this little code snippet:

<?php
$file = 'foo20030903150719820.bar';

$file = preg_replace ('/(^\D*)(\d{4})(\d{2})(\d{2})(\d{2})(\d{2})(\d{2})(\d*)/', '\2-\3-\4 \5:\6:\7.\8', $file);
list ($date, $serial) = explode('.', $file);

print $date.'<br>'.$serial;
?>

will strip out any prefixed or suffixed non-digit characters, add the dashes and colons as appropriate, and split the string into a time/date stamp and a serial number.


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