cut with a string field delimiter

[jmiturbe]

Hello,

How can I get some all the text of a line between two string field separators? For example, how do I get the IP number contained between the words "from" an "at" from the following log?

..........received from 192.168.1.10 at ....

I need to specify from and at as field separators because the log lines are irregular.

Thanks in advance,

jmiturbe

 

[Salem]

Try this

#!/bin/awk -f
match($0,"from.*at") > 0 {
  print substr($0,RSTART+4,RLENGTH-6)
}

 

[Ygor]

To get everything between "from" and "at"...

awk '{ if (match($0,"from .* at&quot)
print substr($0,RSTART+5,RLENGTH-8) }' file1

To get all IP addresses in a file...

awk '{ if (match($0,"[0-9]{1,3}\.[0-9]{1,3}\.[0-9]{1,3}\.[0-9]{1,3}&quot)
print substr($0,RSTART,RLENGTH) }' file1

 

[sanyam]

Here's an example I tried at unix command line and it works:
echo ".....received from 192.168.1.10 at ...." | awk -F'(from|at)' '{print $2}'

 

[PHV]

And what about this ?

sed 's!^.*from !!;s! at.*!' /path/to/yourlogfile

Hope This Help
PH.