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cube root (higher math) 1

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Pinan

IS-IT--Management
Jul 15, 2002
40
US
Does VB have a function to handle cube roots? Seems odd that I can find where to calculate the inverse hyperbolic cotangent, but not cube root...
 
The reason that you won't find that is because is can be done with the exponentiation operator.

The nth root of any number is that number raised to the 1/n power.

So the cube root of 25 would be

CubeRoot = 25 ^ (1/3)

The 5th root would be Root = 25 ^ (1/5) Good Luck
--------------
As a circle of light increases so does the circumference of darkness around it. - Albert Einstein
 
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