CPU Percent

[warmongr]

Anyone have the formula for computing CPU percent from /proc/stat. I assume it is a matter of counting jiffies between intervals and then dividing over total jiffies but I'd like to get your take.

Thanks,
W

 

[KevinADC]

Sounds right.

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- Kevin, perl coder unexceptional!

 

[dmazzini]

I have found something in the net. May be interesting

http://www.uwsg.indiana.edu/hypermail/linux/kernel/9805.0/0402.html

http://backpan.perl.org/authors/id/B/BL/BLOONIX/Linux-Statistics-1.10.readme

dmazzini
GSM/UMTS System and Telecomm Consultant

 

[warmongr]

Thanks,

I'd seen

http://backpan.perl.org/authors/id/B/BL/BLOONIX/Linux-Statistics-1.10.readme

before. I also found this script that eludes to a solution but I'm not sure it's correct. It suggests that the user space jiffy between intervals * 100/hz (100) is how that's calculated. So on a machine that is set to 100HZ, between any interval let's say there is a jiffy difference of 50 that means the user space CPU percent is 50%. (50*100)/100. Here's the link. Am I reading that right?

http://munin.projects.linpro.no/bro...tion-branch/node/node.d.linux/cpu.in?rev=1045