Concatinate a single char to a char*

[timmay3141]

How do you concatinate a single char onto the end of a char*? I tried using the strcat function, but the second parameter it takes is char* so I can't just send the character. Here's an example of what I want to do:

#include <conio.h>
#include <iostream.h>

void main()
{
char* str = &quot;Entered character: &quot;;
char ch;

ch = getch();
// concatinate ch onto the end of str
cout << str << endl;
}

How do I do this?

 

[palbano]

well first you have to have the memory at the end of the string which you do not in your code.

next, there are any number of ways to do that, here is one:

char str[40];  // why 40? i have no idea
char ch = getch();
sprintf(str, "Entered character: %c", ch);
cout << str << endl;

does that help?
-pete

 

[PerFnurt]

As mentioned, there is a number of ways...

Ask yourself &quot;What is a char* ?&quot; - It is an array of chars where the last char is 0.

strlen( ) returns
* the length of the string, or put in another way
* the number of chars before the 0 char, or put in yet another way
* the index of the 0 character.

so if you want to concatenate a string with a char, simply:

.
.
int indexToZeroChar=strlen(str);
str[indexToZeroChar] = ch; // Replace the 0 char with ch
str[indexToZeroChar+1] = 0; // Set a new 0 char after the concatenated char

This assumes str is allocated to hold yet another char though...