Bash script help needed 1

[thedaver]

I want to delete the first instance of a duplicated filename...

I use this bash scriptlet to produce a list of files that have duplicate file names

find ./ | sed s#.*/##g | sort | grep mp3 | uniq -d > duplicate_files

The file "duplicate_files" contains the list.

I need to read this file, perform another "find -iname [filename]" and then delete the first record (probably using "head -1") - which should delete the first found instance of a duplicated file.

Help appreciated.

http://www.surfinbox.com/hosting/

 

[ericbrunson]

Something like this?

cat names | while read name
do 
    print rm $( find ~ -name $file -print | head -1 )
done

And that is *not* a useless use of a cat...

 

[thedaver]

OK, with this code originating the list,

find ./ | sed s#.*/##g | sort | grep txt | uniq -d  > duplicate_files

and this code processing the list

cat duplicate_files | while read name
do
# Remove the echo on the next line
    echo rm -f  \"$( find -iname "$name" -print | tail -1 )\"
done

I was able to delete the last found instance of a duplicate file.

BIG WARNING!!! This will keep killing instances of the found files until you have none if you keep running the second script.

Thanks Eric!

http://www.surfinbox.com/hosting/