All About Time...

[slurpyx]

Am trying to create a simple program that will compute for an employees time in and time out. I just want to know how to compute for the difference of a time in and time out, even if an employee time in 8.00am jan 7 and time out jan 9 8.00am. we get that a lot from here. i just want to compute the time difference or the total time consumed within a time in and time out...

I tried this:
$sec = mktime(10,0,0,1,9,2004) - mktime(8,0,0,1,9,2004);
echo date('H:i:s', $sec); // will echo 18:00:00

How can i convert this into real time? as in total hours and minutes like, i want the above example to produce "2:00".

how can i do this?

 

[slurpyx]

I know that this:

$dateDiff = mktime(12,20,0,04,20,2003) - mktime(11,0,0,04,20,2003);
echo 'Difference in seconds: ' . $dateDiff . '<br />';

echo '<br />Years Difference = '. floor($dateDiff/365/60/60/24);
echo '<br />Months Difference = '. floor($dateDiff/60/60/24/7/4);
echo '<br />Weeks Difference = '. floor($dateDiff/60/60/24/7);
echo '<br />Days Difference = '. floor($dateDiff/60/60/24);
echo '<br />Hours Difference = '. floor($dateDiff/60/60);
echo '<br />Minutes Difference = '. floor($dateDiff/60);

will produce something like:

Difference in seconds: 4800

Years Difference = 0
Months Difference = 0
Weeks Difference = 0
Days Difference = 0
Hours Difference = 1
Minutes Difference = 80

But i want to get the 1:20 hours:mins output? how do i do this?

 

[DRJ478]

You did all the computations you need. All that is left is to assemble the hours and remainder of minutes [modulus 60]:

echo('<br />Hours and minutes = '. floor($dateDiff/60/60).':'.(floor($dateDiff/60)%60));