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Take look at http://users.actcom.co.il/~choo/lupg/tutorials/multi-thread/multi-thread.html This may be very much useful for you. ---Maniraja S

Its up to you to decide, but in DOS you will not get much sophisticated library as Windows. Try OpenGL.

Hi hasanasghar00, see the corrected code below. --Maniraja S #include <stdio.H> #include <iostream.h> #include <conio.h> #include <stdlib.h> #include <alloc.h> #include <string.h> int main(void) { FILE *fptr; char fname[10],temp[10]; int n=0,i=0,j=0,k=0, *bof; char ch,(*addr)[4]; char...

Are your asking the compilation procedures ?. Create the programa using vi editor and compile the c programs by giving the command gcc CProgramName and g++ CppProgramName. ---Maniraja S

Just the macro calls (BAUD or PARITY) are replaced by the defined constants (9600 or 8N1) in the program by the preprocessor. After this preprocessor substitution the compiler will do its work. So 9600, and 8N1 will be treated based on the code. --Maniraja

Hi, Call the function format_agent_code as format_agent_code(rec.agent_code); //just remove the &, which makes lot of difference in the argument type. But the error message is something different, it may be there in some other part of the program. ---Maniraja S

I think you can not use TSR programs to control/Access the activity of a Windows application. You have to choose the Windows schedule programming.

By combining MaheshRathi & Jyrixx ideas I have given a sample program. It may fulfill your requirement. #include <iostream> #include <cstring> using namespace std; typedef union { int iData; double dData; char sData[100]; }DATA; class stackUnion { private : struct { unsigned char...

Can you post the Error ?.

Hi Maschwa, I have posted the code for Unix OS. If your using the Turboc C/C++ IDE for DOS, then do the following changes. 1. Declare one more pointer variable of the type FILE, ie FILE *tStdout; 2. Instead of the statement stdout = fdopen(iNewStdout, &quot;w&quot;); put the following...

The freopen() will close the orginal stream(in our case it is stdout; passed as an argument to this function), but we are having some other way to achive our aim. Use the following code this will solve the problem. #include <stdio.h> int main() { int iNewStdout; FILE *fpStdout...

If you know the number of columns then you can allocate the 2d array like the following also. #include <stdio.h> #include <malloc.h> int main() { int (*p)[3]; int i, j, r; printf(&quot;Enter number of rows : &quot;); scanf(&quot;%d&quot;, &r); p = (int...

Hi jstreich, The given if statement if(index < 0 && index >= arrayLength) will never become true (the arrayLength will not be <= 0). Check it. Maniraja S

An example. #include <iostream> using namespace std; class ArrayObject { int *array; int arrayLength; public : ArrayObject(int i) { arrayLength = i; array = new int[10]; } int & operator [] (int index)...

Hi, Use the following function. void clearStdin() { char cs[10]; gets(cs); } define this function within your program and call this function like clearStdin(); before the the fgets and after the scanf(). These reason for this is that the scanf will store the entered integer into the...

Ok, but few changes. char **b; b = (char **) malloc(256 * sizeof(char *)); put b[0] = (char *) malloc(noOfCharacters * sizeof(char)); or as u said b[i] = &extract[i]; If you want to allocate two dimensional arrays then do like the following. int main() { int (*p)[3]; int i, j...

1. declare a unsigned short int pointer variable. 2, assign the starting address of the memory ( which you want to read) to that pointer variable. Now you can put *pointerVariable and can see the value. If you want you can store it in an array. To see the next element, increment the...

Hi, problem is there in ur strcmp function. You should pass the address of the character array to that function not just the characters itself. If your case replace the if statement which contains the strcmp() in the getString() like the following. if(key == in[p]) it will do everything. One...

#include <stdio.h> int main() { char name[][6] = {&quot;One&quot;, &quot;Two&quot;, &quot;Three&quot;}; char *p1, *p2, *p3; p1 = name[0]; p2 = name[1]; p3 = name[2]; printf(&quot;\nThe characters are %c %c %c&quot;, *p1, *p2, *p3); return 0; }

Hi, Do like the following, it will solv your problem. #include <iostream.h> int main() { char name[100]; while(1) // To terminate the loop press Ctrl C { cin.get(name, 20, '\r'); cout << name << endl; cin.ignore(1000...