CountOfEQUAL OPPORTUNITY CountOfTOTAL
35 211
This is what the fields look like, im not certain if this is helpful in solving this but it 35 have take the class out off a possible 211 people
SELECT DISTINCTROW Count([HQ CO TRNG DATABASE].[EQUAL OPPORTUNITY]) AS [CountOfEQUAL OPPORTUNITY], Count([HQ CO TRNG DATABASE].TOTAL) AS CountOfTOTAL
FROM [HQ CO TRNG DATABASE];
Thanks Duane MS Access MVP, PHV, and Skip!!!!!!!!!!!!!
Thank you for your time,
I'm doing the Count([Take Test])/Count(*) AS [%] expresion in design view of a query, under the Criteria tab, in expression builder, is that correct?
I made the database in about two days but Ive been working on the percentages for about a week now. I have a...
Thank you,
I have a table that looks something like this:
Students Taken Test
1 20071201
2 20071201
3 20071205
4 20071205
5 20071205
6 20080108
7 blank
8 blank
This is multipled by 100...
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