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Recent content by userand
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Filter columns
Could anyone help me a little? Just give some hits how to modify it... Thanks in advance! -
Filter columns
Hello, I need help in the following problem: I have this datarow 0 23 43 67 123 345 565 342 100 42 12 1 0 0 23 43 67 123 345 565 342 100 42 12 1 0 I want to filter out those columns, which are out of the mean vaule +/- standard deviation of the positions of the numbers. Position means the... -
Conversion
Ok, thanks. Just one more thing: could you suggest something to do this in a reverse mode, i.e. if I have only 0 1 0 0 1 0 1 1 1 0 1 0 1 rows, how could I convert these to one just contatining the positions of the "1"-s ? (Probably it is not so easy when the number of columns might varied...) -
Conversion
Yes, I have already tried it, but this case is a bit different, because I have only one row and just the positions of the "1"-s... -
Conversion
Hello, I have the following output from some program: 10 3 7 9 10 the first column is: there should be 10 colums the other columns are the position of some arbitrary character, let's say "1". I need to convert the row above to this line 0 0 1 0 0 0 1 0 1 1 Could anyone help me? -
2d arrays help
Ok, well, let's start again. I have this data # 1st col 2nd col 3rd col 4th col 5th col 6th col 1 4 8 1 3 9 1 1 9 2 1 24 2 4 14 2 2 54 2 3 4 2 4 39 2 1 2 2 1 103 4 2 4 3 2 78 4 4 9 3 1 1 5 1 3 6 4 2 - The 1st and the 4th cols numbering go from 1 to let's say 1000, and... -
2d arrays help
No. You just take into account the $2 and $5 columns as indecies of the 2d array, let's say a[$2,$5]; and you should add $3 and $6 together +=$3 + +=$6 somehow .... -
2d arrays help
Sorry, just a remark: $1==$4 in the sense, that their values are the same; they should not necessery be in the same row, as you might see for example in the beginning 1 4 8 1 3 9 <----- here $1 == $4 1 1 9 2 1 24 <----- here $1 != $4 but we have have to take into account that... -
2d arrays help
Hi, I did a mistake in my explanation. Correction: I have these data file: 1 4 8 1 3 9 1 1 9 2 1 24 2 4 14 2 2 54 2 3 4 2 4 39 2 1 2 2 1 103 4 2 4 3 2 78 4 4 9 3 1 1 5 1 3 6 4 2 And I should get this 1 1 105 1 2 56 1 3 18 1 4 46 2 1 0 2 2 0 2 3 0 2 4 0 3 1 28 3 2 58 3 3 0 3... -
2d arrays help
This part is not so trivial for me: awk '{a[$1,$2]+=$3;a[$4,$5]+=$6;}END{for(i=1;i<=NR;i++)for(i=1;j<=4;j++)print i,j,a[i,j];}' So far this is not working properly. Importent point is that the numbers in the 1st and 4th columns goes from 1 to arbitrary value, let's sat from 1 to 10000; only... -
2d arrays help
Hi all, I have a problem, and cannot see how to solve it, so I need some help. I have a data file like this: 1 4 8 1 3 9 1 1 9 2 1 24 2 4 14 2 2 54 2 3 4 2 4 39 2 1 2 2 1 103 4 2 4 3 2 78 4 4 9 3 1 1 I would like to make a 2d histogram from this data in the following way: - the... -
Print out numbers on display
Nice, thanks. Can you split this line _ _ _ _ 12 _ _ 234 1 7 _ _ 99 _ 9 _ into the following: _ _ _ _ 12 _ _ 234 1 7 _ _ 99 _ 9 _ For example I have 16 columns in a row, and I would like to start a new line after every 4th columns. I did it in this way but not helped so far: awk... -
Print out numbers on display
Hi, I am just wondering how can be solved the following problem: I have the numbers 0 0 0 0 12 0 0 234 1 7 0 0 99 0 9 0 0 Now I would like to convert this to _ _ _ _ 12 _ _ 234 1 7 _ _ 99 _ 9 _ _ I think I should use a[0]="_"; ...etc. but if I have numbers different from 0's it is a... -
Converting numbers
Sorry, my last question makes no sense. It is trivial. But what i would like to ask if there is 1 6 8 1 1 9 2 6 14 2 1 14 4 6 5 How can I get this 6 8 1 1 9 2 6 14 2 1 14 3 0 0 4 6 5 or rather 1 9 0 0 0 0 8 0 0 0 0 0 0 0 0 0 0 2 14 0 0 0 0 14 0 0 0 0 0 0 0 0 0 0 3 0 0 0 0 0 0 0 0 0 0 0 0... -
Converting numbers
Hi, that's nice. Just one more simple question: how can I modify the code if I want to get 1 9 0 0 0 0 8 0 0 0 0 0 0 0 0 0 0 instead of 1 9 0 0 0 0 8 So the number of columns should be 16 in any cases; and for example the second column of 1 6 8 1 1 9 2 6 14 2 1 14 4 6 5 just indicating...
