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Recent content by timmyni
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single command
sorry, pasted the wrong one, SELECT DISTINCT t1.* FROM try1 AS t1 INNER JOIN try1 AS t2 ON t1.age = t2.age AND t1.id <> t2.id -
single command
how about this one select id, age from users where age in ( select age from users group by age having count(*) > 1 ) -
single command
I have a table users( ...... age int .........) I want to pick out the users have same age as anyother users. with one SQL statement. How can I do it?
