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Recent content by slowfish
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email validation
could I send the code to you so you can take a look? many thanks for all your help- slowfish
- Post #19
- Forum: Javascript
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email validation
Still can't get this to work... function checkemail(what) { return ! ( what == "" || /[!\"£$%\^&*()-+=<>,\'#?\\|¬`\/\[\]]/.test(what) || what.indexOf('.') == -1 || what.indexOf('@') == -1 || what.slice(what.lastIndexOf('.')+1,what.length).length < 2 ||...- slowfish
- Post #15
- Forum: Javascript
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email validation
Thanks feherke. What about if I have other fields in the form that I need to check for? Can I put these in the validate(form) function too?- slowfish
- Post #13
- Forum: Javascript
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email validation
Can you help as to how I would do this? tsuji - not sure I understand what you mean by "And you tolerate yourself to produce such thing?" Apologies all, quite new to javascript and the code I used was just copied after a google search. Thanks- slowfish
- Post #11
- Forum: Javascript
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email validation
Apologies, this is the actual code I'm using. Field names are different, both fields are in form "ff". if (document.ff.ref1email.value != "") { var str = new String(document.ff.ref1email.value); var isOK = true; rExp = /[!\"£$%\^&*()-+=<>,\'#?\\|¬`\/\[\]]/ if(...- slowfish
- Post #8
- Forum: Javascript
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email validation
Yes, there are two email fields in the same form (ff)- slowfish
- Post #6
- Forum: Javascript
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email validation
Here's the code. The first email field is ref1email and the second field is ref2email. If ref1email is not a valid email address the alert pops up. If ref1email address amended so correct, form submitted and passes through without any alert that ref2email is invalid. if...- slowfish
- Post #3
- Forum: Javascript
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email validation
Hi I have an email field in my form where javascript email validation works fine on submit. I've recently added another email field but some reason the email validation now doesn't work. Any ideas?- slowfish
- Thread
- Replies: 19
- Forum: Javascript
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CASE and JOINS
Hi Is it possible to use CASE to work out which table to JOIN? Cheers -
this month followed by subsequent months
$mon=$mon+1; $count=$mon+11; for ( $x=$mon; $x<=$count; $x++ ) { if ($x > 12) { $nextmonth = $x-12; } else { $nextmonth = $x; } Got there in the end. Thanks for all your help! -
this month followed by subsequent months
Hi It's the "trick" that I'm after.... I have an array with full month names and am using a for loop. -
this month followed by subsequent months
What's the easiest way of printing this month followed by all the subsequent months, so showing 12 months in total, i.e. - May 2010 June 2010 etc etc March 2011 April 2011 -
COUNT WITH MULTIPLE JOINS
Great thanks for that, it worked. Just had to replace the AND with WHERE. SELECT COUNT(*) AS howmany FROM taskvolsnew WHERE vol NOT IN ( SELECT volref FROM volunteers_types WHERE voltype = '4' ) -
COUNT WITH MULTIPLE JOINS
it's irrelevant how many types the vol is - whenever they are on task it should just be a count of one. need to exclude voltype 4 vols from the count for all tasks they have ever been on
