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Recent content by sjaakdelul
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strip_slashes
This code works: $diagnose = $_POST['diagnose']; $_POST['diagnose'] = ereg_replace("\"",""",stripslashes($diagnose)); Now, I want to add these one: $_POST['diagnose'] = ereg_replace("\'","´",stripslashes($diagnose)) How can i use...- sjaakdelul
- Post #3
- Forum: PHP
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strip_slashes
OK, "hey" becomes \\\\\\\"hey\\\\\\\" but, 'hey becomes So, when the user use ' in the inputfiled, the data gets lost! Is the any solution and answer for this problem?- sjaakdelul
- Post #2
- Forum: PHP
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strip_slashes
I've this form: <html> <head> </head> <body> <? switch ($target) { case "": stap3(); break; case "stap31": stap31(); break; case "stap310": stap310(); break; case "stap4": stap4(); break; } function stap3() {...- sjaakdelul
- Thread
- Replies: 3
- Forum: PHP
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resolutions
Sorry, the url is: http://members.rott.chello.nl/jmolegraaf/GOT/index.html Thx- sjaakdelul
- Post #2
- Forum: HTML, XHTML & CSS
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resolutions
I've create a background image. My website is create within 5 frames, one top, nbottum, main, left and right frame ... The image should be as one background-image at all the frames. I've sliced the images and saved the parts for the different frames. At each frame, I've set the right part of the...- sjaakdelul
- Thread
- Replies: 1
- Forum: HTML, XHTML & CSS
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Hey, At home I had a mysql serve
Can another version of apache or php be the reason for the problem?- sjaakdelul
- Post #3
- Forum: MySQL
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Hey, At home I had a mysql serve
Hey, At home I had a mysql server (3.23), PHP (4.2.2)and an apache server ... until the big crash :( Now, I've saved my files at a server of a friend. But when I run the scripts, I get the follow error: "Warning: mysql_fetch_object(): supplied argument is not a valid MySQL result...- sjaakdelul
- Thread
- Replies: 4
- Forum: MySQL
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Updating variables
This is the goodone: //Execute query $result = mysql_query(" SELECT * from cijferlijst WHERE 1 AND vak = '". $vakkeuze1 . "' "); Thx 4 all- sjaakdelul
- Post #9
- Forum: MySQL
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I am using php4.2.2 and the newest
I am using php4.2.2 and the newest version of mysql. The database CREATE TABLE cijferlijst ( Kwartaal int(1) default NULL, vak varchar(5) default NULL, cijfer1 varchar(4) default NULL, cijfer2 varchar(4) default '-', cijfer3 varchar(4) default '-', cijfer4 varchar(4) default '-'...- sjaakdelul
- Thread
- Replies: 1
- Forum: Microsoft SQL Server: Programming
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Updating variables
It didn't worked ... I've tried 10 other variants, but use a variable in the update or select line still didn't worked ... Anyone knows more about this problem?- sjaakdelul
- Post #7
- Forum: MySQL
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Updating variables
Ok, now I've this select line: //Execute query $sql = 'SELECT * FROM `cijferlijst` WHERE 1 AND `vak` = \'Proj1\' LIMIT 0, 30'; $result = mysql_query($sql); Phpmyadmin advise me to use a variable in the line like this: $sql = 'SELECT * FROM `cijferlijst` WHERE 1 AND `vak` =...- sjaakdelul
- Post #5
- Forum: MySQL
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Updating variables
Hmmz...disapointed, it didn't work I create another file to test the update line. This works and I copy and past it into update2.php: <?php if ( $_POST[vakkeuze]>A ) { $vakkeuze1=$_POST[vakkeuze]; echo "$vakkeuze1<br>"; } else { echo "Voer de juiste vakafkorting...- sjaakdelul
- Post #4
- Forum: MySQL
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Updating variables
I am using php4.2.2 and the newest version of mysql. Database: CREATE TABLE cijferlijst ( Kwartaal int(1) default NULL, vak varchar(5) default NULL, cijfer1 varchar(4) default NULL, cijfer2 varchar(4) default '-', cijfer3 varchar(4) default '-', cijfer4 varchar(4) default '-'...- sjaakdelul
- Thread
- Replies: 8
- Forum: MySQL
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Apache and PHP
Ok, it's working now. I forgot to remove the php.ini file in the php directory ... This file was conflicting with the php.ini file in the directory windows. Thx 4 all- sjaakdelul
- Post #3
- Forum: Linux (server)
