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Recent content by mizt

  1. mizt

    solution to eval(Expr, Value).

    Hi I found this question in a book but it didn't have a solution to it, any have any pointers on how to go about solving it? Heres the problem Define evaluate(Expr, Value) that given an arithmetic expression "Expr" in prefix form with binary operations "add" and...
  2. mizt

    Prolog help

    thats pretty easy.. Something is the member of a list if it is the Head of the list or if it is in the tail of the list.. so member(X, [X,Head]). member(X, [Head,Tail]):- member(X, Tail). Hope that helps.. Euan

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