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Recent content by jfm1
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Print all words that start with a %, one to a line.
I tried that but in csh I got "d': Event not found" as an error msg. But I tried combining sed and awk and finally got what I wanted: cat logfile | sed 's/.*\(%\)/\1/' | awk '{print $1}' This listed the "%words" I was looking for. Thanks for the kick start. Joe -
Print all words that start with a %, one to a line.
Hello, I have a log where every line has a word in it that starts with a % sign. I need to print each line, but only the word that starts with %, no other words or characters. Thanks for your help, Joe -
awk gives an error of " too many fields "
Try using nawk, it works for me when parsing large Openview<br>SNMP records that give that same error when using awk.
