Contact US

Log In

Come Join Us!

Are you a
Computer / IT professional?
Join Tek-Tips Forums!
  • Talk With Other Members
  • Be Notified Of Responses
    To Your Posts
  • Keyword Search
  • One-Click Access To Your
    Favorite Forums
  • Automated Signatures
    On Your Posts
  • Best Of All, It's Free!

*Tek-Tips's functionality depends on members receiving e-mail. By joining you are opting in to receive e-mail.

Posting Guidelines

Promoting, selling, recruiting, coursework and thesis posting is forbidden.

Students Click Here

ODBC functions

How do you pull just the date from a DateTime column? by foxdev
Posted: 15 Sep 00

ODBC provides a function, Left, that can be used to pull just the date portion of a date-time value.  Note that the result is a character expression.

For example, if a date of birth column contains the value "08-Jan-1962 12:00:00", the ODBC command:

select {fn left(dob, 10)} from MyTable

will yield only "08-Jan-1962".

As with all ODBC scalar functions, be sure to use the curly braces {} in the appropriate places, as the ODBC driver looks for these to indicate the section that the driver should interpret.

Back to ODBC/OLAP FAQ Index
Back to ODBC/OLAP Forum

My Archive

Close Box

Join Tek-Tips® Today!

Join your peers on the Internet's largest technical computer professional community.
It's easy to join and it's free.

Here's Why Members Love Tek-Tips Forums:

Register now while it's still free!

Already a member? Close this window and log in.

Join Us             Close