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print first line unconditionally

print first line unconditionally

(OP)
hello,

I'd like to get whole 1st line (header line, makred in blue) printf in each iteration in below for loop.

What I get now is:

CODE --> shell

# cat inputtest
===> hostA: transfer 16/09/2016,00:00:01 - 16/09/2016,23:59:59          5        42.64
===> hostB: transfer 16/09/2016,00:00:01 - 16/09/2016,23:59:59          3        65.24
===> hostA: transfer 17/09/2016,00:00:01 - 17/09/2016,23:59:59          7        22.54
===> hostB: transfer 17/09/2016,00:00:01 - 17/09/2016,23:59:59          7        36.34
# for a in hostA hostB;do echo "---==== $a ====---";{ echo "date files size";grep $a: inputtest|tr -s ' '; } |awk -F"[ |,]" '{printf "%+11s %+10s %+10s\n",$4,$(NF-1),$NF}';echo;done
---==== hostA ====---
                 files       size
 16/09/2016          5      42.64
 17/09/2016          7      22.54

---==== hostB ====---
                 files       size
 16/09/2016          3      65.24
 17/09/2016          7      36.34

# 

what to check in the awk in the loop to achieve this?:

CODE --> output

---==== hostA ====---
       date      files       size
 16/09/2016          5      42.64
 17/09/2016          7      22.54

---==== hostB ====---
       date      files       size
 16/09/2016          3      65.24
 17/09/2016          7      36.34 


RE: print first line unconditionally

(OP)
Update: I've figured it out

CODE --> solution

# for a in hostA hostB;do echo "---==== $a ====---";printf "%+11s %+10s %+10s\n" date files size;grep $a: inputtest|tr -s ' '|awk -F"[ |,]" '{printf "%+11s %+10s %+10s\n",$4,$(NF-1),$NF}';echo;done
---==== hostA ====---
       date      files       size
 16/09/2016          5      42.64
 17/09/2016          7      22.54

---==== hostB ====---
       date      files       size
 16/09/2016          3      65.24
 17/09/2016          7      36.34 

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