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ksh: check if varaible's value ends with specific string

ksh: check if varaible's value ends with specific string

ksh: check if varaible's value ends with specific string

(OP)

here are my tries:

$ a=abc
$ [[ "$a" = @(abc) ]] && echo ends with abc
ends with abc
$ a=aabc
$ [[ "$a" = @(abc) ]] && echo ends with abc
$ [[ "$a" = @(abc)$ ]] && echo ends with abc
$

RE: ksh: check if varaible's value ends with specific string

Hi

CODE

[[ "$a" = *@(abc) ]] && echo ends with abc

# or just

[[ "$a" = *abc ]] && echo ends with abc 
I think you misunderstood the meaning of @(...) sub-patterns. They are meaningful when they enclose a pattern-list ( as man calls them ), so something that describes multiple alternatives, like @(foo|bar) or @([aeiou]).

Feherke.
feherke.ga

RE: ksh: check if varaible's value ends with specific string

As feherke says, the KSH '@()' is supposed to fully contain the pattern or pattern-list. So it should look like this (asterisk inside the parens)...

CODE

[[ "$a" = @(*abc) ]] && print "Ends with 'abc'" 

As he mentions, with pattern as simple as this, it's not really needed, but with more complicated patterns, the whole pattern should be in the parens.

Putting the whole pattern in the parens also lets you include spaces in your pattern...

CODE

STR="1 2 3 4 5"
[[ $STR = @(* 2 3 *) ]] && print "Contains ' 2 3 '" 

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