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Barcode increment with letters and numbers

Barcode increment with letters and numbers

(OP)
I am trying to increment a barcode with values A-Z...0-9 then back to A.
Values like:
AFWK9, AFWL9, AZFL9
Would increment to:
AFWLA, AFXMA, A0FMA

I am trying to use VBA to accomplish and was able to find some code which got me to the place below however my problem is I can't figure out how to handle incrementing the Third, Second and Fourth values and how to handle when the Fourth value is a 9. I've included if statements following true to below If SFourthLetter = 9 but it's not working. If someone can get me on the right track with the Fourth letter and/or the Third letter I can figure out the rest myself. I'm a little green at VBA so please bear with me. Any help you give would be much appreciated. Thank you- Heather

Function IncrementAlpha(strIn As String) As String
'Pass this function your letter string
'Example myNewString = IncrementAlpha("ab")
'will return "ac"

Dim sAlphaBet As String
Dim sFirstLetter As String
Dim sSecondLetter As String
Dim sThirdLetter As String
Dim sFourthLetter As String
Dim sFifthLetter As String
Dim X As Variant
Dim I As Long
sFirstLetter = Left(strIn, 1)
sSecondLetter = Mid(strIn, 2, 1)
sThirdLetter = Mid(strIn, 3, 1)
sFourthLetter = Mid(strIn, 4, 1)
sFifthLetter = Mid(strIn, 5, 1)
sAlphaBet = "A,B,C,D,E,F,G,H,I,J,K,L,M,N,O,P,Q,R,S,T,U,V,W,X,Y,Z,0,1,2,3,4,5,6,7,8,9"
X = Split(sAlphaBet, ",")



If sFifthLetter = "9" Then
'loop to get next first letter
For I = I To UBound(X) - 1
If X(I) = sFourthLetter Then
sFourthLetter = X(I + 1)
sFifthLetter = "A"
sThirdLetter = sThirdLetter
sSecondLetter = sSecondLetter
sFirstLetter = sFirstLetter
Exit For
End If
Next I

Else
'loop to get the next letter
For I = 0 To UBound(X) - 1
If X(I) = sFifthLetter Then
sFifthLetter = X(I + 1)
sFourthLetter = sFourthLetter
sThirdLetter = sThirdLetter
sSecondLetter = sSecondLetter
sFirstLetter = sFirstLetter
Exit For
End If

Next I
End If

IncrementAlpha = sFirstLetter & sSecondLetter & sThirdLetter & sFourthLetter & sFifthLetter
End Function


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