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Home > Forums > Programmers > Web Development > PHP Forum

trying to regex first line of textHelpful Member! 

thread434-1689519
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pushyr (Programmer)
30 Jul 12 13:28
this is perhaps one of the simplest things to do, but after googling i just can't find anything that works. Here's my own concoction, which doesn't work.
...so, how would i regex the first line from a block of text

CODE

preg_match("#^(.*?)\r\n#is", $content00);
feherke (Programmer)
30 Jul 12 14:09
Hi

First of all, this sounds like a bad idea. Regexes are slower that plain text manipulation functions.
  • If $content00 is short, I would use array_shift(explode("\r\n",$content00,2));.
  • If $content00 is long, I would use substr($content00,0,($pos=strpos($content00,"\r\n"))!==false?$pos:strlen($content00));.
By the way, your code works for me. Show us some sample $content00 value and usage example.

Feherke.
http://feherke.github.com/

pushyr (Programmer)
30 Jul 12 14:41
ahh.. ok, i think i know were i went wrong with my initial question. i'm really trying to get the second line...

Quote:


----------------------------------------------------------
http://www.bbc.co.uk/news/

GET /news/ HTTP/1.1
Host: www.bbc.co.uk
User-Agent: Mozilla/5.0 (Macintosh; Intel Mac OS X 10.7; rv:14.0) Gecko/20100101 Firefox/14.0.1
Accept: text/html,application/xhtml+xml,application/xml;q=0.9,*/*;q=0.8
Accept-Language: en-us,en;q=0.5
Accept-Encoding: gzip, deflate
Connection: keep-alive
Referer: http://www.google.co.uk/url?sa=t&rct=j&q=&...
Cookie: NTABS=B8; BBC-UID=4580115552e46478bdcebce241a7cd2b814fb7e3aed8e3f93365dabd39fba7900Mozilla%2f5%2e0%20%28Macintosh%3b%20Intel%20Mac%20OS%20X%2010%2e7%3b%20rv%3a14%2e0%29%20Gecko%2f20100101%20Firefox%2f14%2e0%2e1; ed=1; BGUID=c580a1a5d234e419ea78e67681c3d99953fe069cfe9823098325aa9d791ea520; ckns_policy=111; s1=5015245155C80241; rsi_segs=J08781_10053|J08781_10052|J08781_10058|J08781_10132|J08781_10338|J08781_10340|J08781_10342|J08781_10362|J08781_10398|J08781_10417|J08781_10572|J08781_10608|J08781_10609|J08781_10610|J08781_10611; s_cc=true; s_vnum=1346237563852%26vn%3D2; s_nr=1343645563853; s_ev48=%5B%5BB%5D%5D; s_sq=bbcwglobalprod%3D%2526pid%253Dbbc%252520news%252520%25257C%252520uk%2526pidt%253D1%2526oid%253Dhttp%25253A%25252F%25252Fwww.bbc.co.uk%25252Fnews%25252Ftechnology%25252F%2...; s_sv_sid=914755482672; _em_vt=8c24acf5b8ae7b4f2d369c1c4b765016677ce12930-106766535016a7a1; _em_hl=1; tr_pr1=bbc%20news%20%7C%20uk~%5B2%5D; c=undefinedwww.google.ptwww.google.pt; s_ev49=%5B%5B'Other%2520Referrers'%2C'1343660905153'%5D%5D

HTTP/1.1 200 OK
Date: Mon, 30 Jul 2012 18:37:46 GMT
Server: Apache
Vary: Cookie,X-CDN
Cache-Control: max-age=0
Expires: Mon, 30 Jul 2012 18:37:46 GMT
Access-Control-Allow-Origin: *
Keep-Alive: timeout=5, max=758
Connection: Keep-Alive
Transfer-Encoding: chunked
Content-Type: text/html
----------------------------------------------------------

so the first line is: ----------------------------------------------------------
and the second line i'm after is: http://www.bbc.co.uk/news/
pushyr (Programmer)
30 Jul 12 15:17
thanks for your help feherke... i solved it with this...

$url0 = explode("\r\n", $content00);
$url = $url0[1];

since the text will always be 20 to 30 lines, i think this is ok?
Helpful Member!  feherke (Programmer)
31 Jul 12 2:31
Hi

Yes, explode()ing that should not be so big effort.

In case you have PHP 5.4, you can write it shorter as :

CODE --> PHP-5.4

$url = explode("\r\n", $content00)[1];

As extra caution I would think about splitting on \n and removing the remaining \r with rtrim() :

CODE --> PHP

$url0 = explode("\n", $content00);
$url = rtrim($url0[1], "\r");
Of course, if you can be sure about the DOS line endings, this is unnecessary. ( If you also want compatibility with MacOS line endings too, that will get back to regular expressions. )

Feherke.
http://feherke.github.com/

pushyr (Programmer)
31 Jul 12 7:47
cheers feherke!
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